{"id":2949,"date":"2024-03-16T17:35:52","date_gmt":"2024-03-16T16:35:52","guid":{"rendered":"https:\/\/www.iangrandjean.com\/blog\/?p=2949"},"modified":"2024-04-08T17:42:25","modified_gmt":"2024-04-08T16:42:25","slug":"simple-question-really","status":"publish","type":"post","link":"http:\/\/www.iangrandjean.com\/blog\/2024\/03\/16\/simple-question-really\/","title":{"rendered":"Simple question really&#8230;"},"content":{"rendered":"\n<p>&#8230;how many images can I get onto a memory card?<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><a href=\"https:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/03\/Capture-decran-2024-03-16-a-17.33.53.png\"><img loading=\"lazy\" decoding=\"async\" width=\"430\" height=\"459\" src=\"https:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/03\/Capture-decran-2024-03-16-a-17.33.53.png\" alt=\"\" class=\"wp-image-2950\" style=\"width:295px;height:auto\" srcset=\"http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/03\/Capture-decran-2024-03-16-a-17.33.53.png 430w, http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/03\/Capture-decran-2024-03-16-a-17.33.53-281x300.png 281w\" sizes=\"auto, (max-width: 430px) 100vw, 430px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p>Well, ok, at first sight, it seems very simple &#8211; divide the capacity of the card by the size of the image files and hey presto!<\/p>\n\n\n\n<p>Except no &#8211; you can&rsquo;t just do this. For a start, despite the fact that cards are shown with a capacity in <strong>Giga<\/strong> bytes (or Giga octets) this number needs to be modified.<\/p>\n\n\n\n<p>A single gigabyte is in fact 1024 <strong>Megabytes<\/strong> of space. So now we multiply the indicated card capacity by 1024.<\/p>\n\n\n\n<p>For a 128Gb card :   128 * 1024 = 131072 Mb<\/p>\n\n\n\n<p>Now take of up to 7% of this space for the directories and space needed by the car to reference everything written on to it and we&rsquo;re left with<\/p>\n\n\n\n<p>131072 &#8211; 7% (9175 Mb) = 121896 Mb<\/p>\n\n\n\n<p>Now we can take our &lsquo;average&rsquo; file size (I estimate 33Mb for my 24 megapixel sensor &#8211; this changes with file type RAW or JPEG, compression, loss or lossless, 12 or 14 bit etc. and also the detail in the image&#8230;)<\/p>\n\n\n\n<p>121896 \/ 33 = 3693 images<\/p>\n\n\n\n<p>According to the official NIKON manual for the Z6ll I should be able to record 2400 image files on a 128Gb card &#8211; this calculation (confirmed by other sites) indicates a 30% increase&#8230;<\/p>\n\n\n\n<p>I&rsquo;m off to the Highlands in the fall &#8211; with a bit of luck, and a 512Gb memory card, I won&rsquo;t even need to do a backup while I&rsquo;m away. But, of course I will as I don&rsquo;t trust ANY memory card system, and a simple download to my NVMe backup will reassure me \ud83d\ude42 <\/p>\n\n\n\n<p>PS The answer seems to be \u00ab\u00a0in excess of 14,000 images on a 512Go card\u00a0\u00bb<\/p>\n\n\n\n<p><strong>UPDATE<\/strong><\/p>\n\n\n\n<p>Interestingly, I posted this question on the NIKON RUMURS forum &#8211; naturally no-one has responded (<em>the people there don&rsquo;t actually own any cameras to make images, so they&rsquo;re incapable of knowing how many &lsquo;virtual&rsquo; images they would be able to get on their &lsquo;virtual&rsquo; memory cards<\/em>). <\/p>\n\n\n\n<p>I also mailed Thom Hogan &#8211; and received a reply &#8211; I rest my case. If you need information, go to the pros &#8211; thanx Thom.<\/p>\n\n\n\n<p><strong>Further Update<\/strong><\/p>\n\n\n\n<p>It seems the answer was in fact hiding in plain sight&#8230;<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><a href=\"https:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-scaled.jpg\"><img loading=\"lazy\" decoding=\"async\" width=\"768\" height=\"1024\" src=\"https:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-768x1024.jpg\" alt=\"\" class=\"wp-image-2979\" style=\"width:323px;height:auto\" srcset=\"http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-768x1024.jpg 768w, http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-225x300.jpg 225w, http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-1152x1536.jpg 1152w, http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-1536x2048.jpg 1536w, http:\/\/www.iangrandjean.com\/blog\/wp-content\/uploads\/2024\/04\/IMG_1885-scaled.jpg 1920w\" sizes=\"auto, (max-width: 706px) 89vw, (max-width: 767px) 82vw, 740px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p>Here&rsquo;s the control panel of one of my NIKON cameras and even switched off it displays how many (approximately) images can be stored on the card (in this case a 512Gb)<\/p>\n\n\n\n<p>Sometimes you can&rsquo;t see the wood for the trees&#8230;..<\/p>\n","protected":false},"excerpt":{"rendered":"<p>&#8230;how many images can I get onto a memory card? Well, ok, at first sight, it seems very simple &#8211; divide the capacity of the card by the size of the image files and hey presto! Except no &#8211; you can&rsquo;t just do this. For a start, despite the fact that cards are shown with &hellip; <\/p>\n<p class=\"link-more\"><a href=\"http:\/\/www.iangrandjean.com\/blog\/2024\/03\/16\/simple-question-really\/\" class=\"more-link\">Continuer la lecture<span class=\"screen-reader-text\"> de &laquo;&nbsp;Simple question really&#8230;&nbsp;&raquo;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-2949","post","type-post","status-publish","format-standard","hentry","category-non-classe"],"_links":{"self":[{"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/posts\/2949","targetHints":{"allow":["GET"]}}],"collection":[{"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/comments?post=2949"}],"version-history":[{"count":6,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/posts\/2949\/revisions"}],"predecessor-version":[{"id":2981,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/posts\/2949\/revisions\/2981"}],"wp:attachment":[{"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/media?parent=2949"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/categories?post=2949"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/www.iangrandjean.com\/blog\/wp-json\/wp\/v2\/tags?post=2949"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}